Exp. 1
AIM- Calculate the molarity of unknown sodium carbonate given in bottle B. You are provided with M/20 standard solution of Sodium carbonate solution in Bottle A. By Titration method using methyl orange as an indicator and intermediate solution is HCl.
Theory-a) this is neutralisation titration.
b) This is double titration.
c) Methyl orange gives orange colour in basic and pink colour in acidic medium.
Chemical Reaction -
Na2CO3 + 2HCl 2NaCl + H2O + CO2
Apparaturs and Matericals required -
Burette, pipette, conical flask, funnel, burette stand, Na2CO3 solution, HCl solution, indicator methyl orange, distiled water etc.
Method-
a) Titration of std. Na2CO3 solution with HCl solution
Wash Burette with water followed by washing with HCl solution. Then fill burette with HCl solution by placing it in stand.
New pitpette out 20 ml of Std. solution in conical flask. Add 2-3 drops of indicator in the flask. Allow the solution of burette to add in the flask drop by drop with continous stinning.
At the equvatence point, pink colour appears. Note the burette reading to calculate the molority of solution repeat the process to get concordant reading.
b) Titration of Unknown solution with intermediate solution
Take intermediate solution in burette, and pipette out 20 ml in conical flask. Add 2-3 drops of indicator.
Now add solution from burette in the flask drop by drop, fill pink colour comes at end point.
Obseration Table 1
Obseration Table 2
Calculation -
a) Molarity of Given Na2CO3 = M/20
b) a1M1V1 = a2M2V2
a1 = 2
a2 = 1
M1 = M/20 Molarity of std. Na2CO3 solution.
M2 = Molarity of Intermediate HCl solution.
V1 = Volume of std. Na2CO3 solution.
V2 = Volume of Intermediate HCl solution.
M2 = =2M
c) Molarity of unknown Sodium Carbonate solution.
2M3V3 = M4V4
M3 = Molarity of unknown Na2CO3 solution.= ?
M4 = Molarity of Intermediate HCl solution. =2M
V3 = Volume of unknown Na2CO3 solution.= 20 ml
V4 = Volume of Intermediate HCl solution. =
M3 = =M
=M
Result- Molarity of unknown sodium carbonate is ................... mol/Lit.
AIM- Calculate the molarity of unknown sodium carbonate given in bottle B. You are provided with M/20 standard solution of Sodium carbonate solution in Bottle A. By Titration method using methyl orange as an indicator and intermediate solution is HCl.
Theory-a) this is neutralisation titration.
b) This is double titration.
c) Methyl orange gives orange colour in basic and pink colour in acidic medium.
Chemical Reaction -
Na2CO3 + 2HCl 2NaCl + H2O + CO2
Apparaturs and Matericals required -
Burette, pipette, conical flask, funnel, burette stand, Na2CO3 solution, HCl solution, indicator methyl orange, distiled water etc.
Method-
a) Titration of std. Na2CO3 solution with HCl solution
Wash Burette with water followed by washing with HCl solution. Then fill burette with HCl solution by placing it in stand.
New pitpette out 20 ml of Std. solution in conical flask. Add 2-3 drops of indicator in the flask. Allow the solution of burette to add in the flask drop by drop with continous stinning.
At the equvatence point, pink colour appears. Note the burette reading to calculate the molority of solution repeat the process to get concordant reading.
b) Titration of Unknown solution with intermediate solution
Take intermediate solution in burette, and pipette out 20 ml in conical flask. Add 2-3 drops of indicator.
Now add solution from burette in the flask drop by drop, fill pink colour comes at end point.
Obseration Table 1
Obseration Table 2
Calculation -
a) Molarity of Given Na2CO3 = M/20
b) a1M1V1 = a2M2V2
a1 = 2
a2 = 1
M1 = M/20 Molarity of std. Na2CO3 solution.
M2 = Molarity of Intermediate HCl solution.
V1 = Volume of std. Na2CO3 solution.
V2 = Volume of Intermediate HCl solution.
M2 = =2M
c) Molarity of unknown Sodium Carbonate solution.
2M3V3 = M4V4
M3 = Molarity of unknown Na2CO3 solution.= ?
M4 = Molarity of Intermediate HCl solution. =2M
V3 = Volume of unknown Na2CO3 solution.= 20 ml
V4 = Volume of Intermediate HCl solution. =
M3 = =M
=M
Result- Molarity of unknown sodium carbonate is ................... mol/Lit.
